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The Crossing Ladders Problem
The Crossing Ladders Problem is a classic trigonometry problem
which has been challenging high school students for generations. This
website describes the problem and presents the solution in complete detail.
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Anything but Trivial
Trig students (and even some professors!) who see the problem
often believe that the solution requires only a trivial application of the Pythagorean
Theorem. In fact, however, this classic problem is much more difficult
than it first appears.
Colin Foster
The solution was provided by Colin Foster, who deserves all the credit for the solution presented
here.
Exclusive Source
This website is the exclusive source for
the Crossing Ladders Problem. Here you will find a complete,
detailed and step-by-step explanation of solution, with equations and
diagrams.
We created this website because we could find no
other website that gives a complete solution to the Crossing Ladders
Problem.
About Joe
Joe has been working on the problem since his Father
first posed the problem when Joe was a high school sophomore. Over the
years, he spent perhaps hundreds of hours trying to solve it.
At a family dinner in early 2001, Joe told his
nephew, Nick, the story of his 40-year quest for a solution. Joe's father
remembered the problem but not the solution.
Joe surveyed the Internet and found
several websites that discussed the problem but none that provided the
solution. One of them is maintained by Colin Foster.
Joe emailed Colin to discuss the problem, and Colin provided Joe with
the solution, which is detailed here.
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The Problem
Here is one version of the classic Crossing Ladders
problem, as has been presented to trigonometry students for decades:
A painter wants to measure the width of the floor but does not have a ruler.
Instead, the painter has two ladders, one 25' and the other 20'. The painter leans one ladder from the corner of
the room to the far wall, and he leans the other ladder from the far corner to the near
wall. The painter is only 5' tall (a short painter), and the point where the two ladders intersect
is exactly 5' off the floor. How wide is the floor?
Thus, in this version, there are three variables: a 25' ladder, a 20'
ladder, and a 5' vertical line that marks the height where the two ladders
intersect. As this classic problem is retold, the lengths of these three
variables change, but the basic problem remains the same.
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Diagram of the Problem
Let's diagram the
problem with a series of diagrams, beginning with an empty room.
The diagram above shows the room before the painter
arrives. Notice that the room has two walls and a floor, and they are at
right angles (90 degrees). We will label the two corners as points A and
C. We are trying to determine the length, x, which is the line (AC).
Now let's add the first ladder:
As shown above, the ladder forms the line (CG) (in red), which
is given as 25'. Now the second ladder:
The second ladder (in green) forms the
line (AE), which is given as 20'. Notice that the first ladder is also
shown (in black), and the two ladders cross. Let's look at the third
variable:
As described in the problem, the painter measures that the point
where the two ladders intersect is exactly 5' high. In the diagram above,
the line from this point to the floor (blue) is labeled (OE). Notice that
this line forms a right angle (90 degrees) to the floor.
Now we can look at the complete diagram of the initial problem,
which shows the two walls, the floor, the two ladders, the line where they
intersect, and the points (A, B, etc.) used to identify the triangles
and lines.:
Click Here to Continue
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