Step 2: Ratio of AC and
DE
There are many websites that explain the proof and
explanation of the Pythagorean Theorem, so they will not be described
here. Instead, we shall continue with the solution to the Crossing
Ladders Problem and find the ratio between AC and DE.
Triangle AEC
Consider the triangle AEC:
According to the Pythagorean Theorem, the square of the
hypotenuse equals the square of the base plus the square of the height.
In the triangle AEC above:
AE2 = AC2 + CE2
We know that the value of the line AE is 20, and we can substitute:
202 = AC2 + CE2
and simplify:
AC2 = CE2 - 400
By looking at the diagram above, we notice that the line CE is
comprised of the line CD plus the line DE, so be can substitute, in
place of CE2 , the value (CD + DE)2 as follows:
AC2 = (CD + DE)2 - 400
Notice that the value of line CD is the same as the value of line OB,
and we know that line OB equals 5. Thus we can substitute for CD
with this value:
AC2 = (5 + DE)2 - 400
Further simplifying:
AC2 = (25 + 10DE + DE2) - 400
Simplifying again, we derive the fourth basic equation and complete
Step 2 of the solution:
AC2 = DE2 + 10DE - 375
(4)
Click Here to Continue
|