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Crossing Ladders
                                       The Classic Problem in Trigonometry





Step 2:  Ratio of AC and DE

There are many websites that explain the proof and explanation of the Pythagorean Theorem, so they will not be described here.  Instead, we shall continue with the solution to the Crossing Ladders Problem and find the ratio between AC and DE.

Triangle AEC

Consider the triangle AEC:

According to the Pythagorean Theorem, the square of the hypotenuse equals the square of the base plus the square of the height.  In the triangle AEC above:

AE2 = AC2 + CE2

We know that the value of the line AE is 20, and we can substitute:

202 = AC2 + CE2

and simplify:

AC2 = CE2 - 400

By looking at the diagram above, we notice that the line CE is comprised of the line CD plus the line DE, so be can substitute, in place of CE2 , the value (CD + DE)2 as follows:

AC2 = (CD + DE)2 - 400

Notice that the value of line CD is the same as the value of line OB, and we know that line OB equals 5.  Thus we can substitute for CD with this value:

AC2 = (5 + DE)2 - 400

Further simplifying:

AC2 = (25 + 10DE + DE2) - 400

Simplifying again, we derive the fourth basic equation and complete Step 2 of the solution:

AC2 = DE2 + 10DE - 375             (4)

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